4d^2-5d-6=0

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Solution for 4d^2-5d-6=0 equation:



4d^2-5d-6=0
a = 4; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·4·(-6)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*4}=\frac{-6}{8} =-3/4 $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*4}=\frac{16}{8} =2 $

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